LeetCode
Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
For example,
Given the following matrix:
Given the following matrix:
[ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ]
You should return
[1,2,3,6,9,8,7,4,5]
.
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Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. | |
For example, | |
Given the following matrix: | |
[ | |
[ 1, 2, 3 ], | |
[ 4, 5, 6 ], | |
[ 7, 8, 9 ] | |
] | |
You should return [1,2,3,6,9,8,7,4,5]. | |
public class SpiralMatrix { | |
public ArrayList<Integer> spiralOrder(int[][] matrix) { | |
// Start typing your Java solution below | |
// DO NOT write main() function | |
ArrayList<Integer> result=new ArrayList<Integer> (); | |
if (matrix==null|| matrix.length==0){ | |
return result; | |
} | |
int beginX=0; | |
int endX=matrix[0].length-1; | |
int beginY=0; | |
int endY=matrix.length-1; | |
while(true){ | |
for (int col=beginX; col<=endX; col++){ | |
result.add(matrix[beginY][col]); | |
} | |
if (++beginY>endY){ | |
break; | |
} | |
for (int row=beginY; row<=endY; row++){ | |
result.add(matrix[row][endX]); | |
} | |
if (--endX<beginX){ | |
break; | |
} | |
for (int col=endX; col>=beginX; col--){ | |
result.add(matrix[endY][col]); | |
} | |
if (--endY<beginY){ | |
break; | |
} | |
for (int row=endY; row>=beginY; row--){ | |
result.add(matrix[row][beginX]); | |
} | |
if (++beginX>endX){ | |
break; | |
} | |
} | |
return result; | |
} | |
} |
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