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Single Number | |
Total Accepted: 7988 Total Submissions: 17558 My Submissions | |
Given an array of integers, every element appears twice except for one. Find that single one. | |
Note: | |
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? | |
hint: | |
1^1=0; | |
1^1^5^5^3=3 | |
public class Solution { | |
public int singleNumber(int[] A) { | |
if (A==null||A.length==0){ | |
return -1;// throw Enception | |
} | |
int result=A[0]; | |
for (int i=1; i<A.length; i++){ | |
result^=A[i]; | |
} | |
return result; | |
} | |
} |
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