Given a linked list, remove the nth node from the end of list and return its head.
For example,
Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5.
Note:
Given n will always be valid.
Try to do this in one pass.
Given n will always be valid.
Try to do this in one pass.
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/** | |
* Definition for singly-linked list. | |
* public class ListNode { | |
* int val; | |
* ListNode next; | |
* ListNode(int x) { | |
* val = x; | |
* next = null; | |
* } | |
* } | |
*/ | |
public class Solution { | |
public ListNode removeNthFromEnd(ListNode head, int n) { | |
if (head==null){ | |
return head; | |
} | |
ListNode remove=head; | |
ListNode last=head; | |
ListNode preHead=new ListNode (-1); | |
preHead.next=head; | |
ListNode pre=preHead; | |
while (n>1){ | |
if (last.next==null){ | |
return head; | |
} | |
last=last.next; | |
n--; | |
} | |
while (last.next!=null){ | |
last=last.next; | |
pre=pre.next; | |
remove=remove.next; | |
} | |
pre.next=remove.next; | |
return preHead.next; | |
} | |
} |
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