Saturday, April 5, 2014

Remove Nth Node From End of List (Java)

Given a linked list, remove the nth node from the end of list and return its head.
For example,
   Given linked list: 1->2->3->4->5, and n = 2.

   After removing the second node from the end, the linked list becomes 1->2->3->5.
Note:
Given n will always be valid.
Try to do this in one pass.



/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
if (head==null){
return head;
}
ListNode remove=head;
ListNode last=head;
ListNode preHead=new ListNode (-1);
preHead.next=head;
ListNode pre=preHead;
while (n>1){
if (last.next==null){
return head;
}
last=last.next;
n--;
}
while (last.next!=null){
last=last.next;
pre=pre.next;
remove=remove.next;
}
pre.next=remove.next;
return preHead.next;
}
}

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